AP EAMCET · Maths · Circle
If the inverse point of the point \((3,2)\) with respect to the circle \(\mathrm{x}^2+\mathrm{y}^2-2 \mathrm{x}+4 \mathrm{y}-4=0\) is \((l, \mathrm{~m})\) then \((2 l+19 \mathrm{~m})=\)
- A \(3\)
- B \(1\)
- C \(0\)
- D \(-1\)
Answer & Solution
Correct Answer
(C) \(0\)
Step-by-step Solution
Detailed explanation
Given circle is \(x^2+y^2-2 x+4 y-4=0\) \(\therefore\) Centre \(=(1,-2)\) and radius \(=\sqrt{1+4+4}=3\) We have inverse of point \(P(\alpha, \beta)\) w.r. to circle whose centre \((h, k)\) and radius \(\mathrm{r}\) is \[ x=\lambda(\alpha-h)+h, y=\lambda(\beta-k)+k, \]…
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