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AP EAMCET · PHYSICS · Electromagnetic Induction

The energies required to set up in a cube of side \(10 \mathrm{~cm}\)
(i) a uniform electric field of \(10^7 \mathrm{Vm}^{-1}\) and
(ii) a uniform magnetic field of \(0.25 \mathrm{Wbm}^{-2}\) are respectively about
\[
\left(\mu_0=4 \pi \times 10^{-7} \mathrm{Hm}^{-1}, \varepsilon_0=8.9 \times 10^{-12} \mathrm{Fm}^{-1}\right)
\]

  1. A 0.445 J, 25 J
  2. B 4.45 J, 2.5 J
  3. C 44.5 J, 25 J
  4. D 0.44 J, 2.5 J
Verified Solution

Answer & Solution

Correct Answer

(A) 0.445 J, 25 J

Step-by-step Solution

Detailed explanation

Energy densities are \(u_E=\frac{1}{2} \varepsilon_0 E^2\) \[ u_B=\frac{1}{2} \frac{B^2}{\mu_0} \] So, energy required to setup a uniform electric field in cube of side \(10 \mathrm{~cm}\) is…