AP EAMCET · PHYSICS · Electromagnetic Induction
The energies required to set up in a cube of side \(10 \mathrm{~cm}\)
(i) a uniform electric field of \(10^7 \mathrm{Vm}^{-1}\) and
(ii) a uniform magnetic field of \(0.25 \mathrm{Wbm}^{-2}\) are respectively about
\[
\left(\mu_0=4 \pi \times 10^{-7} \mathrm{Hm}^{-1}, \varepsilon_0=8.9 \times 10^{-12} \mathrm{Fm}^{-1}\right)
\]
- A 0.445 J, 25 J
- B 4.45 J, 2.5 J
- C 44.5 J, 25 J
- D 0.44 J, 2.5 J
Answer & Solution
Correct Answer
(A) 0.445 J, 25 J
Step-by-step Solution
Detailed explanation
Energy densities are \(u_E=\frac{1}{2} \varepsilon_0 E^2\) \[ u_B=\frac{1}{2} \frac{B^2}{\mu_0} \] So, energy required to setup a uniform electric field in cube of side \(10 \mathrm{~cm}\) is…
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