AP EAMCET · PHYSICS · Motion In One Dimension
The displacement \((x)\) and time \((t)\) graph of a particle moving along a straight line is shown in the figure. The average velocity of the particle in the time of 10 s is
- A \(2 \mathrm{~m} \mathrm{~s}^{-1}\)
- B \(4 \mathrm{~m} \mathrm{~s}^{-1}\)
- C \(6 \mathrm{~m} \mathrm{~s}^{-1}\)
- D \(8 \mathrm{~m} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(A) \(2 \mathrm{~m} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\( \text{Average velocity} = \frac{\text{Change in displacement}}{\text{Change in time}} \) \( \text{Average velocity} = \frac{x_f - x_i}{t_f - t_i} \) \( \text{Average velocity} = \frac{20 \text{ m} - 0 \text{ m}}{10 \text{ s} - 0 \text{ s}} \)…
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