AP EAMCET · PHYSICS · Motion In Two Dimensions
The centripetal acceleration of a particle in uniform circular motion is \(18 \mathrm{~ms}^{-2}\). If the radius of the circular path is 50 cm , the change in velocity of the particle in a time of \(\frac{\pi}{18} \mathrm{~s}\) is
- A \(9 \mathrm{~ms}^{-1}\)
- B \(2 \mathrm{~ms}^{-1}\)
- C \(3 \mathrm{~ms}^{-1}\)
- D \(6 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(3 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
In circular motion, \(\begin{aligned} & a_c=\frac{v^2}{r} \\ & \therefore \quad v=\sqrt{a_c \cdot r}=\sqrt{18 \times 50 \times 10^{-2}}=3 \mathrm{~m} / \mathrm{s} \end{aligned}\) Also, \(w=\frac{\mathrm{v}}{\mathrm{r}}=\frac{3}{50 \times 10^{-2}}=6 \mathrm{rad} / \mathrm{s}\)…
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