AP EAMCET · PHYSICS · Thermal Properties of Matter
The change in density of mercury, when it is heated from \(10^{\circ} \mathrm{C}\) to \(60^{\circ} \mathrm{C}\) is (The coefficient of volume expansion of mercury is \(18.2 \times 10^{-5} \mathrm{~K}^{-1}\) )
- A \(1.82 \%\)
- B \(0.91 \%\)
- C \(9.1 \%\)
- D \(0.45 \%\)
Answer & Solution
Correct Answer
(B) \(0.91 \%\)
Step-by-step Solution
Detailed explanation
\(\rho=\frac{\mathrm{m}}{\mathrm{V}}\) \(\frac{\Delta \rho}{\rho}=\frac{\Delta V}{V}=\frac{V_0 Y \Delta T}{V_0}=Y \Delta T\) So, \(\frac{\Delta \rho}{\rho} \times 100=\mathrm{Y} \Delta \mathrm{T} \times 100\)…
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