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AP EAMCET · PHYSICS · Center of Mass Momentum and Collision

A ball of mass 0.5 kg moving horizontally at 10 m s-1 strikes a vertical wall and rebounds with speed v. The magnitude of the change in linear momentum is found to be 8.0 kg m s-1. The magnitude of v is,

  1. A 6.0 m s-1
  2. B 9.0 m s-1
  3. C 26.0 m s-1
  4. D 13.0 m s-1
Verified Solution

Answer & Solution

Correct Answer

(A) 6.0 m s-1

Step-by-step Solution

Detailed explanation

Linear momentum is a vector quantity. Initial momentum =+m×10 i^. Final momentum =-mv i^ Change in linear momentum =-10m i^-mv i^=-10+vm i^ Therefore, 10+v×0.5=8⇒v=16-10=6 m s-1
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