AP EAMCET · PHYSICS · Magnetic Effects of Current
An infinitely long straight conductor is bent into shape as shown in figure. It carries a current \(I \mathrm{~A}\) and the radius of circular loop is \(r \mathrm{~m}\). The magnetic induction at the centre of the circular loop is
- A \(\frac{\mu_0 /(\pi-1)}{2 \pi r}\)
- B \(\frac{\mu_0 /(\pi+1)}{2 \pi r}\)
- C \(\frac{\mu_0 /(2 \pi-1)}{2 \pi r}\)
- D \(\frac{\mu_0 /(2 \pi+1)}{2 \pi r}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu_0 /(\pi-1)}{2 \pi r}\)
Step-by-step Solution
Detailed explanation
The given situation is shown in the figure, Net magnetic field at \(O\), \(B=B\) due to straight wire \(P Q\) (upward) \(+B\) due to straight wire \(C D\) (upward) \(+B\) due to circular wire (downward)…
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