AP EAMCET · PHYSICS · Electrostatics
A circular plate sheet of radius \(10 \mathrm{~cm}\) is placed in a uniform electric field of \(2 \sqrt{3} \times 10^5 \mathrm{NC}^{-1}\), making an angle of \(60^{\circ}\) with the field. Then, find the electric flux through the sheet.
- A \(1.36 \times 10^2 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- B \(9.42 \times 10^3 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- C \(0.515 \times 10^2 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
- D \(0.515 \times 10^4 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Answer & Solution
Correct Answer
(B) \(9.42 \times 10^3 \mathrm{Nm}^2 \mathrm{C}^{-1}\)
Step-by-step Solution
Detailed explanation
Given that, radius of plate, \[ \begin{aligned} R & =10 \mathrm{~cm} \\ & =10 \times 10^{-2} \mathrm{~m} \end{aligned} \] Uniform electric field, \(E=2 \sqrt{3} \times 10^5 \mathrm{NC}^{-1}\) Since, the angle between plate and electric field is \(60^{\circ}\). Then, angle…
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