AP EAMCET · PHYSICS · Thermodynamics
Match the following lists.
\begin{array}{|c|c|c|c|}
\hline & List I & & List II \\
\hline A & \begin{array}{l}\text { Zeroth law of } \\
\text { thermodynamics }\end{array} & 1 & \begin{array}{l}\text { Direction of flow of } \\
\text { heat }\end{array} \\
\hline B & \begin{array}{l}\text { First law of } \\
\text { thermodynamics }\end{array} & \| & Work done is zero \\
\hline\underline{\mathrm{C}} & Free expansion of a gas & III & Thermal equilibrium \\
\hline D & \begin{array}{l}\text { Second law of } \\
\text { Thermodynamics }\end{array} & IV & \begin{array}{l}\text { Law of conservation } \\
\text { of energy }\end{array} \\
\hline
\end{array}
The correct answer is
\(\begin{array}{lccccccccc} & \text { A } & \text { B } & \text { C } & \text { D } \end{array}\)
- A \(\begin{array} \text { II } & \text { IV } & \text { III } & \text { I }\end{array}\)
- B \(\begin{array}& \text { III } & \text { IV } & \text { II } & \text { I }\end{array}\)
- C \(\begin{array}& \text { III } & \text { I } & \text { II } & \text { IV }\end{array}\)
- D \(\begin{array}& \text { I } & \text { III } & \text { IV } & \text { II }\end{array}\)
Answer & Solution
Correct Answer
(B) \(\begin{array}& \text { III } & \text { IV } & \text { II } & \text { I }\end{array}\)
Step-by-step Solution
Detailed explanation
(i) Zeroth law of thermodynamics states about thermal equilibrium of different states in contact. (ii) First law is energy conservation law. (iii) In free expansion of gases, work done is always zero. (iv) Second law of thermodynamics discusses about flow of heat in thermal…
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