AP EAMCET · PHYSICS · Magnetic Effects of Current
In hydrogen atom an electron is making \(6.6 \times 10^{15} \mathrm{rev} / \mathrm{s}\) around the nucleus of radius \(0.47 Å\). The magnetic field induction produced at the centre of the orbit is nearly
- A \(0.14 w b m ~ m^{-2}\)
- B \(1.4 \mathrm{wb} \mathrm{m}^{-2}\)
- C \(14 w b m^{-2}\)
- D \(140 w b^{-2}\)
Answer & Solution
Correct Answer
(C) \(14 w b m^{-2}\)
Step-by-step Solution
Detailed explanation
In hydrogen atom, \(\mathrm{f}=6.6 \times 10^{15} \mathrm{H}_{\mathrm{z}}, \mathrm{r}=0.47 \mathrm{~A}^{\circ}\) \(\therefore \quad \mathrm{I}=\frac{\mathrm{e}}{\mathrm{T}}=\mathrm{ef}=1.6 \times 10^{-19} \times 6.6 \times 10^{15}=10.56 \times 10^4 \mathrm{~A}\)…
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