AP EAMCET · PHYSICS · Semiconductors
In a \(p\) - \(n-p\) transistor working as a common base amplifier, when the current gain is 0.96 and emitter current is \(7.2 \mathrm{~mA}\), the base current is
- A \(0.4 \mathrm{~mA}\)
- B \(0.2 \mathrm{~mA}\)
- C \(0.29 \mathrm{~mA}\)
- D \(0.35 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(C) \(0.29 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
In common base amplifier for \(p-n-p\) transistor, current gain, \(\alpha=0.96\) Emitter current, \(I_E=7.2 \mathrm{~mA}\) We know that,…
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