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AP EAMCET · PHYSICS · Dual Nature of Matter

If the threshold wavelength of light for photoelectric emission to take place from a metal surface is \(6250 Å\), then the work function of the metal is
(Planck's constant \(=6.6 \times 10^{-34} \mathrm{Js}\) )

  1. A \(3.98 \mathrm{~eV}\)
  2. B \(1.98 \mathrm{~eV}\)
  3. C \(2.98 \mathrm{~eV}\)
  4. D \(4.98 \mathrm{~eV}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1.98 \mathrm{~eV}\)

Step-by-step Solution

Detailed explanation

\( \phi = \frac{hc}{\lambda_0} \) \( \phi = \frac{6.6 \times 10^{-34} \times 3 \times 10^8}{6250 \times 10^{-10}} \) \( \phi = 3.168 \times 10^{-19} \mathrm{~J} \) \( \phi = \frac{3.168 \times 10^{-19}}{1.6 \times 10^{-19}} \mathrm{~eV} \) \( \phi = 1.98 \mathrm{~eV} \)
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