AP EAMCET · PHYSICS · Dual Nature of Matter
If the de Broglie wavelength of an electron is 2 nm, then its kinetic energy is nearly
(Planck's constant \(=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s}\) and mass of electron \(=9 \times 10^{-31} \mathrm{~kg}\) )
- A 0.48 eV
- B 0.68 eV
- C 0.38 eV
- D 0.25 eV
Answer & Solution
Correct Answer
(C) 0.38 eV
Step-by-step Solution
Detailed explanation
\(KE = \frac{h^2}{2m\lambda^2}\) \(KE = \frac{(6.6 \times 10^{-34} \mathrm{~J~s})^2}{2 \times (9 \times 10^{-31} \mathrm{~kg}) \times (2 \times 10^{-9} \mathrm{~m})^2}\) \(KE = \frac{43.56 \times 10^{-68}}{72 \times 10^{-49}} \mathrm{~J}\)…
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