AP EAMCET · PHYSICS · Current Electricity
If current of 80 A is passing through a straight conductor of length 10 m, then the total momentum of electrons in the conductor is \(\left(\right.\) mass of electron \(=9.1 \times 10^{-31} \mathrm{~kg}\) and charge of electron \(\left.=1.6 \times 10^{-19} \mathrm{C}\right)\)
- A \(910 \times 10^{-9} \mathrm{Ns}\)
- B \(910 \times 10^{-11} \mathrm{Ns}\)
- C \(455 \times 10^{-9} \mathrm{Ns}\)
- D \(455 \times 10^{-11} \mathrm{Ns}\)
Answer & Solution
Correct Answer
(D) \(455 \times 10^{-11} \mathrm{Ns}\)
Step-by-step Solution
Detailed explanation
\( P = \frac{L m_e I}{e} \) \( P = \frac{10 \times 9.1 \times 10^{-31} \times 80}{1.6 \times 10^{-19}} \) \( P = 4550 \times 10^{-12} \mathrm{~Ns} \) \( P = 455 \times 10^{-11} \mathrm{~Ns} \)
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