AP EAMCET · PHYSICS · Electrostatics
A body of mass \(1 \mathrm{~g}\) and carrying a charge \(10^{-8} \mathrm{C}\) passes from two points \(P\) and \(Q . P\) and \(Q\) are at electric potentials. \(600 \mathrm{~V}\) and \(0 \mathrm{~V}\), respectively. The velocity of the body at \(Q\) is \(20 \mathrm{cms}^{-1}\). It velocity in \(\mathrm{ms}^{-1}\) at \(P\) is
- A \(\sqrt{0.028}\)
- B \(\sqrt{0.056}\)
- C \(\sqrt{0.56}\)
- D \(\sqrt{5.6}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{0.028}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} m & =1 \mathrm{~g}=10^{-3} \mathrm{~kg}, \\ v & =20 \mathrm{~cm} / \mathrm{s}=20 \times 10^{-20} \mathrm{~m} / \mathrm{s} \\ q & =10^{-8} \mathrm{C} \\ V_p & =600 \mathrm{volt} \\ V_Q & =0 \text { volt } \end{aligned} \] Work done in moving the charge from…
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