AP EAMCET · PHYSICS · Laws of Motion
As shown in the figure, a force \(F\) is applied on a block of mass \(\sqrt{3} \mathrm{~kg}\) placed on a rough horizontal surface. The maximum value of F for the block not to move is (Coefficient of static friction between the block and the surface is \(\frac{1}{2 \sqrt{3}}\) and acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 5 N
- B 10 N
- C 15 N
- D 20 N
Answer & Solution
Correct Answer
(D) 20 N
Step-by-step Solution
Detailed explanation
\(N = mg + F \sin 60^\circ\) \(F \cos 60^\circ = \mu_s N\) \(F \cos 60^\circ = \mu_s (mg + F \sin 60^\circ)\) \(F \cdot \frac{1}{2} = \frac{1}{2\sqrt{3}} (\sqrt{3} \cdot 10 + F \cdot \frac{\sqrt{3}}{2})\) \(F \frac{1}{2} = 5 + \frac{F}{4}\) \(2F = 20 + F\) \(F = 20 \mathrm{~N}\)
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