AP EAMCET · PHYSICS · Motion In Two Dimensions
At a certain height, a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of \(10 \sqrt{3} \mathrm{~ms}^{-1}\). The horizontal distance between the two fragments, when their displacement vectors are inclined at \(60^{\circ}\) relative to each other is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
- A \(40 \sqrt{3} \mathrm{~m}\)
- B \(60 \sqrt{3} \mathrm{~m}\)
- C \(240 \sqrt{3} \mathrm{~m}\)
- D \(480 \sqrt{3} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(60 \sqrt{3} \mathrm{~m}\)
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