AP EAMCET · PHYSICS · Alternating Current
An \(R-L-C\) circuit consists of a \(150 \Omega\) resistor, \(20 \mu \mathrm{F}\) capacitor and a \(500 \mathrm{mH}\) inductor connected in series with a \(100 \mathrm{~V}\) AC supply. The angular frequency of the supply voltage is \(400 \mathrm{rad} \mathrm{s}^{-1}\). The phase angle between current and the applied voltage is
- A \(\tan ^{-1}(0.8)\)
- B \(\tan ^{-1}(0.25)\)
- C \(\tan ^{-1}(0.6)\)
- D \(\tan ^{-1}(0.5)\)
Answer & Solution
Correct Answer
(D) \(\tan ^{-1}(0.5)\)
Step-by-step Solution
Detailed explanation
In \(R-L-C\) series circuit \(\begin{aligned} R=150 \Omega, C & =20 \mu \mathrm{F} \\ & =2 \times 10^{-5} \mathrm{~F}\end{aligned}\) \(L=500 \mathrm{mH}=0.5 \mathrm{H}\) Supply voltage, \(V=100 \mathrm{~V}\) Angular frequency, \(\omega=400 \mathrm{rads}^{-1}\) Now,…
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