AP EAMCET · PHYSICS · Current Electricity
The charge \(q\) (in coulomb) passing through a \(10 \mathrm{~ohm}\) resistor as a function of time \(t\) (in second) is given by \(q\) \(=3 t^2-2 t+6\). The potential difference across the ends of the resistor at time \(t=5 \mathrm{~s}\) is
- A 120 V
- B 240 V
- C 140 V
- D 280 V
Answer & Solution
Correct Answer
(D) 280 V
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{q}=3 \mathrm{t}^2-2 \mathrm{t}+6 \\ & \begin{aligned} \therefore & \text { Current, } \mathrm{I}=\frac{\mathrm{dq}}{\mathrm{dt}}=\frac{\mathrm{d}}{\mathrm{dt}}\left(3 \mathrm{t}^2-2 \mathrm{t}+6\right) \\ & =(6 \mathrm{t}-2) \\ \therefore & A t…
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