AP EAMCET · PHYSICS · Semiconductors
An \(n-p-n\) transistor is connected in common-emitter configuration as shown in the figure. If the collector current is \(5 \mathrm{~mA}\), \(V_{B E}=0.6 \mathrm{~V}, V_{C E}=3 \mathrm{~V}\) and common-emitter current amplification factor is 50 , then the values of \(R_1\) and \(R_2\) are respectively.
- A \(1 \mathrm{k} \Omega, 74 \mathrm{k} \Omega\)
- B \(74 \mathrm{k} \Omega, 1 \mathrm{k} \Omega\)
- C \(37 \mathrm{k} \Omega, 2 \mathrm{k} \Omega\)
- D \(2 \mathrm{k} \Omega, 37 \mathrm{k} \Omega\)
Answer & Solution
Correct Answer
(B) \(74 \mathrm{k} \Omega, 1 \mathrm{k} \Omega\)
Step-by-step Solution
Detailed explanation
In given circuit, \(V_{C C}=i_B R_B+V_{B E}\) \[ \Rightarrow \quad R_B=R_1=\frac{V_{C C}-V_{B E}}{i_B} \] As, \(i_B=\frac{i_C}{\beta}=\frac{5 \times 10^{-3}}{50}=1 \times 10^{-4} \mathrm{~A}\)…
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