AP EAMCET · PHYSICS · Magnetic Effects of Current
An electron having kinetic energy of \(100 \mathrm{eV}\) circulates in a path of radius \(10 \mathrm{~cm}\) in a magnetic field. The magnitude of magnetic field \(|\mathbf{B}|\) is approximately [Mass of electron \(=0.5 \mathrm{MeV} \mathrm{c}^{-2}\), where \(\mathrm{c}\) is the velocity of light].
- A \(3.3 \times 10^{-4} \mathrm{~T}\)
- B \(2.6 \times 10^{-4} \mathrm{~T}\)
- C \(1.70 \times 10^{-4} \mathrm{~T}\)
- D \(4.3 \times 10^{-4} \mathrm{~T}\)
Answer & Solution
Correct Answer
(A) \(3.3 \times 10^{-4} \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
Kinetic energy of electron, \(\begin{aligned} K & =100 \mathrm{eV} \\ & =100 \times 1.5 \times 10^{-19} \mathrm{~J}=1.6 \times 10^{-17} \mathrm{~J}\end{aligned}\) Radius of circular path, \(r=10 \mathrm{~cm}=0.1 \mathrm{~m}\) Mass of electron, \(m=0.5 \mathrm{MeVc}^{-2}\)…
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