AP EAMCET · PHYSICS · Semiconductors
A Zener diode is made by
- A heavily doping both \(p\) - and \(n\)-sides of a \(p-n\) junction diode
- B heavily doping the \(p\)-side and lightly doping the \(n\)-side of a \(p-n\) junction diode
- C lightly doping the \(p\)-side and heavily doping the \(n\)-side of a \(p-n\) junction diode
- D lightly doping both \(p\) - and \(n\)-sides of a \(p-n\) junction diode
Answer & Solution
Correct Answer
(A) heavily doping both \(p\) - and \(n\)-sides of a \(p-n\) junction diode
Step-by-step Solution
Detailed explanation
A Zener diode is made by heavily doping both \(p\) and \(n\)-sides of the junction. Because of heavily doping, a very thin \(\left(\angle 10^{-6} \mathrm{~m}\right)\) depletion region is formed between the \(p\) and \(n\)-sides, and hence the electric field of the junction is…
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