AP EAMCET · PHYSICS · Laws of Motion
A wire of length 2.5 m is fixed at one end and a box of mass 4 kg is tied at the other end. If the wire rotates in a horizontal circle about the fixed end with \(\frac{2}{\pi}\) rotations per second, then the tension in the wire is
- A 16 N
- B 32 N
- C 64 N
- D 160 N
Answer & Solution
Correct Answer
(D) 160 N
Step-by-step Solution
Detailed explanation
\(\omega = 2\pi f = 2\pi \left(\frac{2}{\pi}\right) = 4 \text{ rad/s}\) \(T = mL\omega^2 = 4 \text{ kg} \times 2.5 \text{ m} \times (4 \text{ rad/s})^2 = 160 \text{ N}\)
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