AP EAMCET · PHYSICS · Thermal Properties of Matter
A wall has two layers \(A\) and \(B\), each made of different materials. Both layers are of same thickness. But, the thermal conductivity of material \(A\) is twice that of \(B\). If in the steady state, the temperature difference across the wall is \(24^{\circ} \mathrm{C}\), then the temperature difference across the layer \(B\) is
- A \(8^{\circ} \mathrm{C}\)
- B \(12^{\circ} \mathrm{C}\)
- C \(16^{\circ} \mathrm{C}\)
- D \(20^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(16^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Let \(K_A\) and \(K_B\) be the thermal conductivity of material \(A\) and \(B\), respectively. Let \(T_1\) be the temperature of \(A\) and \(T_2\) be the temperature of \(B\). At steady state, rate of flow of heat is given by,…
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