AP EAMCET · PHYSICS · Waves and Sound
A transverse wave is represented by the equation \(y=2 \sin (30 t-40 x)\) and the measurements of distances are in meters, then the velocity of propagation is
- A \(15\ ms{-1}\)
- B \(0.75\ ms{-1}\)
- C \(3.75\ ms{-1}\)
- D \(300\ ms{-1}\)
Answer & Solution
Correct Answer
(B) \(0.75\ ms{-1}\)
Step-by-step Solution
Detailed explanation
We have \(y=2 \sin (30 t-40 x)\) The standard transverse wave is \(y=A \sin (\omega t-k x)\) So, \(\omega=30\) and \(k=40\) On comparing, we get \(v=\frac{\omega}{k}=\frac{30}{40}=0.75 \mathrm{~m} / \mathrm{s}\)
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