AP EAMCET · Maths · Quadratic Equation
If \(a, b, c \in R\) are such that \(4 a+2 b+c>0\) and \(a x^2+b x+c=0\) has no real roots, then the value of \((c+a)(c+b)\) is
- A greater than ab
- B less than bc
- C greater than ca
- D less than ab + bc + ca
Answer & Solution
Correct Answer
(A) greater than ab
Step-by-step Solution
Detailed explanation
Since, the equation \(a x^2+b x+c=0\) have no real roots and \(4 a+2 b+c>0\) \[ \begin{aligned} \therefore \quad a+b+c & >0 \\ & \left\{\because a x^2+b x+c>0, \forall x \in R\right\} \end{aligned} \] So,…
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