AP EAMCET · PHYSICS · Work Power Energy
A train of mass \(10^6 \mathrm{~kg}\) is moving at a constant speed of 108 kmph. If the frictional force acting on it is 0.5 N per 100 kg, then the power of the train is
- A 300 kW
- B 150 kW
- C 75 kW
- D 225 kW
Answer & Solution
Correct Answer
(B) 150 kW
Step-by-step Solution
Detailed explanation
\(v = 108 \mathrm{~kmph} = 108 \times \frac{5}{18} \mathrm{~m/s} = 30 \mathrm{~m/s}\) \(F_{\text{friction}} = \frac{10^6 \mathrm{~kg}}{100 \mathrm{~kg}} \times 0.5 \mathrm{~N} = 10000 \times 0.5 \mathrm{~N} = 5000 \mathrm{~N}\)…
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