AP EAMCET · PHYSICS · Rotational Motion
A thin circular ring and a circular disc of equal mass are rolling without sliding. If their linear velocities are equal and the total kinetic energy of the disc is 6 J, then the total kinetic energy of the ring is
- A 6 J
- B 3 J
- C 8 J
- D 4 J
Answer & Solution
Correct Answer
(C) 8 J
Step-by-step Solution
Detailed explanation
\( KE_d = \frac{1}{2} M v^2 + \frac{1}{2} I_d \omega^2 = \frac{1}{2} M v^2 + \frac{1}{2} (\frac{1}{2} M R^2) (\frac{v}{R})^2 = \frac{3}{4} M v^2 \) \( 6 = \frac{3}{4} M v^2 \implies M v^2 = 8 \)…
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