AP EAMCET · PHYSICS · Laws of Motion
A system consists of two springs connected in series and each having the spring constant \(10 \mathrm{Nm}^{-1}\). The minimum work required to stretch this system by \(\mathrm{l} \mathrm{cm}\) in erg is
- A \(1500\)
- B \(2000\)
- C \(3000\)
- D \(2500\)
Answer & Solution
Correct Answer
(D) \(2500\)
Step-by-step Solution
Detailed explanation
For series combination, effective force constant is given by \(\frac{1}{K_{\text {eff }}}=\frac{1}{K_1}+\frac{1}{K_2}\) Here, \(\quad K_1=K_2=10 \mathrm{~N} / \mathrm{m}\) \(\Rightarrow \quad \frac{1}{K_{\text {eff }}}=\frac{1}{10}+\frac{1}{10}=\frac{1}{5}\) or…
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