AP EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{8}{x^8}\left[\begin{array}{l}1-\cos \left(\frac{x^2}{2}\right)-\cos \left(\frac{x^2}{4}\right) \\ +\cos \left(\frac{x^2}{2}\right) \cdot \cos \left(\frac{x^2}{4}\right)\end{array}\right]\) is equal to
- A \(\frac{1}{4}\)
- B \(\frac{1}{8}\)
- C \(\frac{1}{16}\)
- D \(\frac{1}{32}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{32}\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0} \frac{8}{x^8}\left(1-\cos \left(\frac{x^2}{2}\right)-\cos \left(\frac{x^2}{4}\right)+\cos \left(\frac{x^2}{2}\right) \cdot \cos \left(\frac{x^2}{4}\right)\right)\)…
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