AP EAMCET · PHYSICS · Mechanical Properties of Solids
A steel rod of radius \(20 \mathrm{~mm}\) and length of \(2 \mathrm{~m}\) is acted upon by a force of \(400 \mathrm{kN}\) along the length. The values of stress and strain are respectively
\(\left(Y_{\text {steel }}=2 \times 10^{11} \mathrm{Nm}^{-2}\right)\)
- A \(1.96 \times 10^8 \mathrm{Nm}^{-2}, 0.16 \%\)
- B \(3.18 \times 10^8 \mathrm{Nm}^{-2}, 0.16 \%\)
- C \(3.18 \times 10^8 \mathrm{Nm}^{-2}, 0.32 \%\)
- D \(4 \times 10^8 \mathrm{Nm}^{-2}, 0.2 \%\)
Answer & Solution
Correct Answer
(B) \(3.18 \times 10^8 \mathrm{Nm}^{-2}, 0.16 \%\)
Step-by-step Solution
Detailed explanation
Radius of rod, \(\mathrm{r}=20 \mathrm{~mm}=20 \times 10^{-3} \mathrm{~m}\) Length of rod, \(L=2 \mathrm{~m}\) Force, \(\mathrm{F}=400 \mathrm{~K} \mathrm{~N}=400 \times 10^3 \mathrm{~N}\) \(\mathrm{Y}_{\text {steel }}=2 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}\) Stress…
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