AP EAMCET · PHYSICS · Electrostatics
A solid of mass 1 kg has \(6 \times 10^{24}\) atoms. If one electron is removed from every one atom of \(0.005 \%\) of the atoms, then the charge gained by the solid is
- A \(+24 \mathrm{C}\)
- B \(+48 \mathrm{C}\)
- C \(+96 \mathrm{C}\)
- D \(+60 \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(+48 \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(N_{loss} = N_{total} \times \frac{0.005}{100}\) \(N_{loss} = 6 \times 10^{24} \times 5 \times 10^{-5} = 3 \times 10^{20}\) \(Q = N_{loss} \times e\) \(Q = 3 \times 10^{20} \times 1.6 \times 10^{-19} \mathrm{C}\) \(Q = +48 \mathrm{C}\)
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