AP EAMCET · PHYSICS · Oscillations
A simple pendulum, suspended from the ceiling of a lift, has a period of oscillation \(T\), when the lift is at rest. If the lift starts moving upwards with an acceleration \(a=3 \mathrm{~g}\), then the new period will be
- A \(2 T\)
- B \(4 T\)
- C \(\frac{T}{3}\)
- D \(\frac{T}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{T}{2}\)
Step-by-step Solution
Detailed explanation
Given that, \(T\) be the time period of simple pendulum when lift is at rest. Then, \(T=2 \pi \sqrt{\frac{l}{g}}\) ...(i) When the lift is moving upwards with an acceleration \(a=3 g\), the new time period will be \(T^{\prime}=2 \pi \sqrt{\frac{l}{g+a}}\)…
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