AP EAMCET · PHYSICS · Alternating Current
A resistor and an inductor are connected in series to an AC source of voltage \(150 \sin (100 \pi t+\pi)\) volt. If the current in the circuit is \(5 \sin \left(100 \pi t+\frac{2 \pi}{3}\right)\) ampere, then the average power dissipated and the resistance of the resistor are respectively
- A \(187.5 \mathrm{~W}, 30 \Omega\)
- B \(187.5 \mathrm{~W}, 15 \Omega\)
- C \(375 \mathrm{~W}, 30 \Omega\)
- D \(375 \mathrm{~W}, 15 \Omega\)
Answer & Solution
Correct Answer
(B) \(187.5 \mathrm{~W}, 15 \Omega\)
Step-by-step Solution
Detailed explanation
Given, peak voltage, \(V_0=150 \mathrm{~V}\) Peak current, \[ I_0=5 \] Phase difference between voltage and current, \[ \phi=\pi-\frac{2 \pi}{3}=\frac{\pi}{3}=60^{\circ} \] Now, average power in \(R-L\) circuit,…
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