AP EAMCET · PHYSICS · Motion In Two Dimensions
A projectile is thrown in the upward direction making an angle of \(60^{\circ}\) with the horizontal with a velocity of \(140 \mathrm{~ms}^{-1}\). Then the time after which its velocity makes an angle \(45^{\circ}\) with the horizontal is (Acceleration due to gravity, \(g=10 \mathrm{~ms}^{-2}\) )
- A \(0.5124 \mathrm{~s}\)
- B \(51.24 \mathrm{~s}\)
- C \(5.124 \mathrm{~s}\)
- D \(512.4 \mathrm{~s}\)
Answer & Solution
Correct Answer
(C) \(5.124 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Given, angle of projection, \(\theta=60^{\circ}\) and velocity, \(u=140 \mathrm{~ms}^{-1}\) This velocity have divided into two components, horizontal component, \(u_x=u \cos 60^{\circ}=140 \cos 60^{\circ}\) and vertical component, \(u_y=u \sin 60^{\circ}=140 \sin 60^{\circ}\)…
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