AP EAMCET · PHYSICS · Thermal Properties of Matter
Power radiated by a black body at temperature \(T_1\) is \(P\) and it radiates maximum energy at a wavelength \(\lambda_1\). If the temperature of the black body is changed from \(T_1\) to \(T_2\), it radiates maximum energy at a wavelength \(\frac{\lambda_1}{2}\). The power radiated at \(T_2\) is
- A \(2 P\)
- B \(4 P\)
- C \(8 P\)
- D \(16 P\)
Answer & Solution
Correct Answer
(D) \(16 P\)
Step-by-step Solution
Detailed explanation
We have, \(P \propto T^4 \propto \frac{1}{\lambda^4} \Rightarrow \frac{P_1}{P_2}=\left(\frac{\lambda_2}{\lambda_1}\right)^4\) \(\begin{aligned} \frac{P_1}{P_2} & =\frac{1}{16} \\ P_2 & =16 P_1=16 P\end{aligned}\)
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