AP EAMCET · PHYSICS · Electrostatics
A neutral ammonia \(\left(\mathrm{NH}_3\right)\) in its vapour state has an electric dipole moment of magnitude \(5 \times 10^{-30} \mathrm{C}\)-m. How far apart are the molecules centres of positive and negative charge.
- A \(4.125 \times 10^{-12} \mathrm{~m}\)
- B \(3.125 \times 10^{-12} \mathrm{~m}\)
- C \(3.125 \times 10^{-6} \mathrm{~m}\)
- D \(4.125 \times 10^{-6} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(3.125 \times 10^{-12} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Dipole moment, \(\mathrm{p}=5 \times 10^{-30} \mathrm{C}-\mathrm{m}\) The charge on neutral \(\mathrm{NH}_3\) is \(\mathrm{q}=7+1 \times 3=10 \mathrm{e}\)…
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