AP EAMCET · PHYSICS · Thermodynamics
A Carnot engine having an efficiency 1/5 as a heat engine, is used as a refrigerator. If the work done on the system is 50 J, then the
amount of energy absorbed from the reservoir at lower temperature is
- A 90 J
- B 99 J
- C 200 J
- D 1 J
Answer & Solution
Correct Answer
(C) 200 J
Step-by-step Solution
Detailed explanation
Efficiency of Carnot engine, \(\eta=\frac{1}{5}\) Work done on the system, W = 50 J Coefficient of performance of a refrigerator, \(\begin{aligned} \beta & =\frac{1-\eta}{\eta} \\ & =\frac{1-\frac{1}{5}}{\frac{1}{5}}=\frac{4}{5} \times \frac{5}{1}=4\end{aligned}\)…
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