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AP EAMCET · PHYSICS · Mechanical Properties of Solids

A metal wire with circular cross section and length one metre is pulled with tensile force of \(1000 \mathrm{~N}\) on each side. For the wire to be stretched not more than \(0.25 \mathrm{~cm}\), the minimum diameter of the wire required is (Young's modulus of the metal \(=10^{11} \mathrm{~Pa}\), take \(\sqrt{\pi}=1.77\) )

  1. A \(1.13 \mathrm{~mm}\)
  2. B \(2.26 \mathrm{~mm}\)
  3. C \(4.12 \mathrm{~mm}\)
  4. D \(3.1 \mathrm{~mm}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2.26 \mathrm{~mm}\)

Step-by-step Solution

Detailed explanation

Tensile force, \(\mathrm{F}=1000 \mathrm{~N}\) Length, \(L=1 \mathrm{~m}\) Change in length, \(\Delta \mathrm{L}=0.25 \times 10^{-2} \mathrm{~m}\) Young modulus of the metal, \(Y=10^{11} \mathrm{pa}\)…