AP EAMCET · PHYSICS · Electromagnetic Induction
A long solenoid with 2000 turns per meter has a small loop of radius \(3 \mathrm{~cm}\) placed inside the solenoid normal to its axis. If the current through the solenoid increases steadily from \(1.5 \mathrm{~A}\) to \(5.5 \mathrm{~A}\) in \(\frac{\pi^2}{100} \mathrm{~s}\), the induced emf in the loop is
- A \(0.144 \mathrm{mV}\)
- B \(0.288 \mathrm{mV}\)
- C \(0.072 \mathrm{mV}\)
- D \(0.316 \mathrm{mV}\)
Answer & Solution
Correct Answer
(B) \(0.288 \mathrm{mV}\)
Step-by-step Solution
Detailed explanation
Key idea Magnetic field inside a solenoid of infinite length is given by expression \(B=\mu_0 n i\) where, \(n=\) number of turns per unit length. Given, number of turns in solenoid, \(n=2000\), current through solenoid, \(i_i=1.5 \mathrm{~A}\) and \(i_f=5.5 \mathrm{~A}\) So,…
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