AP EAMCET · PHYSICS · Laws of Motion
A block of mass 18.5 kg kept on a smooth horizontal surface is pulled by a rope of 3 m length by a horizontal force of 40 N applied to the other end of the rope. If the linear density of the rope is \(0.5 \mathrm{kgm}^{-1}\) and initially the block is at rest. The time in which the block moves a distance of 9 m is
- A 3s
- B 5s
- C 7s
- D 9s
Answer & Solution
Correct Answer
(A) 3s
Step-by-step Solution
Detailed explanation
\(\mathrm{M}=18.5 \mathrm{~kg}, \mathrm{~F}=40 \mathrm{~N}\) \(\mu=0.5 \mathrm{~kg} \mathrm{~m}^{-1}\) Acceleration of the block-rope system is \(a=\frac{F}{M+\mu \times 3}=\frac{40}{18.5+0.5 \times 3}=2 \mathrm{~ms}^{-2}\) Time to travel the block through distance S is…
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