AP EAMCET · PHYSICS · Thermodynamics
A Carnot engine takes \(3 \times 10^6\) calories of heat from reservoir at \(627^{\circ} \mathrm{C}\) and gives it to a sink at \(27^{\circ} \mathrm{C}\). The work done by the engine is
- A zero
- B \(8.4 \times 10^6 \mathrm{~J}\)
- C \(4.2 \times 10^6 \mathrm{~J}\)
- D \(16.8 \times 10^6 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(8.4 \times 10^6 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Heat taken by Carnot engine, \[ Q=3 \times 10^6 \mathrm{cal}=4.2 \times 3 \times 10^6 \mathrm{~J} \] Temperature of reservoir (source) \[ T_1=(627+273) \mathrm{K}=900 \mathrm{~K} \] Temperature of sink, \[ T_2=(27+273) \mathrm{K}=300 \mathrm{~K} \] We know that, efficiency of…
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