AP EAMCET · PHYSICS · Motion In Two Dimensions
A bullet fired from a gun falls at a distance half of its maximum range. The angle of projection of the bullet is
- A \(45^{\circ}\)
- B \(60^{\circ}\)
- C \(30^{\circ}\)
- D \(15^{\circ}\)
Answer & Solution
Correct Answer
(D) \(15^{\circ}\)
Step-by-step Solution
Detailed explanation
As, we know that for a projectile motion, maximum range, \(R_{\max }=\frac{u^2}{g} \text { and } h_{\max }=\frac{R_{\max }}{4}\) Given, \(\quad R=\frac{R_{\max }}{2}\) \(\Rightarrow \quad \frac{R_{\max }}{2}=\frac{u^2}{2 g}=R\) ...(i) where, \(R=\frac{u^2 \sin 2 \theta}{g}\)…
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