AP EAMCET · PHYSICS · Dual Nature of Matter
A bulb of power \(660 \mathrm{~W}\) radiates uniformly in all directions. The pressure exerted by the radiation on the surface at a distance of \(5 \mathrm{~m}\) is
- A \(5 \times 10^{-8} \mathrm{~Pa}\)
- B \(2 \times 10^{-9} \mathrm{~Pa}\)
- C \(7 \times 10^{-9} \mathrm{~Pa}\)
- D \(\frac{3}{\pi} \times 10^{-8} \mathrm{~Pa}\)
Answer & Solution
Correct Answer
(C) \(7 \times 10^{-9} \mathrm{~Pa}\)
Step-by-step Solution
Detailed explanation
Radiation pressure on a surface at a distance \(r\) from a bulb of power \(P\) is gives as, Radiation pressure \(=\frac{P}{4 \pi r^2 \cdot c}\)(for perfectly absorbing surface) Here, \(P=660 \mathrm{~W}, r=5 \mathrm{~m}, c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\) So, radiation…
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