AP EAMCET · PHYSICS · Laws of Motion
A body of mass \(1 \mathrm{~kg}\) is moving with a velocity \(10 \mathrm{~ms}^{-1}\) due to a constant force on a horizontal rough surface having coefficient of kinetic friction 0.4 . If the constant force is removed, the body comes to rest in a time (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(2.5 \mathrm{~s}\)
- B \(4 \mathrm{~s}\)
- C \(0.4 \mathrm{~s}\)
- D \(0.25 \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(2.5 \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
Mass of body, \(\mathrm{m}=1 \mathrm{~kg}\) velocity, \(v=10 \mathrm{~m} / \mathrm{s}\) Coefficient of kinetic friction, \(\mu=0.4\) from the equation of motion…
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