AP EAMCET · PHYSICS · Motion In Two Dimensions
A body is projected at \(t=0\) with a velocity \(10 \mathrm{~ms}^{-1}\) at an angle of \(60^{\circ}\) with the horizontal. The radius of curvature of its trajectory at \(t=1 s\) is \(R\). Neglecting air resistance and taking acceleration due to gravity \(g=10 \mathrm{~ms}^{-2}\), the value of \(R\) is :
- A \(2.5 m\)
- B \(10.3 m\)
- C \(2.8 m\)
- D \(5.1m\)
Answer & Solution
Correct Answer
(C) \(2.8 m\)
Step-by-step Solution
Detailed explanation
Step 1. Given Data: Initial velocity, \(u=10 \mathrm{~m} / \mathrm{s}\) Angle of projection, \(\theta=60^{\circ}\) Radius of curvature at \(t=1 s\) is \(R\) Acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}\) Step 2. Finding the radius of curvature: Resolving the…
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