AP EAMCET · Maths · Pair of Lines

If the bisectors of the pair of lines $x^{2} - 2 m x y - y^{2} = 0$ is represented by $x^{2} - 2 n x y - y^{2} = 0$ , then

A $m n + 1 = 0$
B $m n - 1 = 0$
C $m + n = 0$
D $m - n = 0$

Verified Solution

Answer & Solution

Correct Answer

(A) $m n + 1 = 0$

Step-by-step Solution

Detailed explanation

Given equation is x2-2mxy-y2=0 .....1 Compare the given equation with ax2+2hxy+by2=0 ......2 We have, a=1, h=-m and b=-1 Now the equation of the bisector of the angle between the pair of lines in equation 1 is x2-y2a-b=xyh ⇒x2-y21--1=xy-m…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From AP EAMCET

Explore more questions on app

If the bisectors of the pair of lines x2-2mxy-y2=0 is represented by x2-2nxy-y2=0, then

Step-by-step Solution

If the bisectors of the pair of lines $x^{2} - 2 m x y - y^{2} = 0$ is represented by $x^{2} - 2 n x y - y^{2} = 0$ , then