AP EAMCET · PHYSICS · Motion In One Dimension
A ball is thrown upward from the ground with an initial speed of \(v\). At the same instant, another ball is dropped from a building of height \(20 \mathrm{~m}\). If the balls are at the same height after \(0.8 \mathrm{~s}\), then the magnitude of \(v\) is
(Take, acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(15 \mathrm{~ms}^{-1}\)
- B \(25 \mathrm{~ms}^{-1}\)
- C \(12.5 \mathrm{~ms}^{-1}\)
- D \(18.5 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(25 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
The given situation is shown below Both balls meet at point \(C\) after \(0.8 \mathrm{~s}\) i.e Let \[ t_1=t_2=0.85 \] \[ \therefore \quad B C=20-h \] For the first ball,…
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