AP EAMCET · Maths · Probability
When a coin is tossed 6 times, the probability of getting more heads than tails is
- A \(\frac{13}{32}\)
- B \(\frac{15}{32}\)
- C \(\frac{9}{32}\)
- D \(\frac{11}{32}\)
Answer & Solution
Correct Answer
(D) \(\frac{11}{32}\)
Step-by-step Solution
Detailed explanation
Total outcomes are \(2^6=64\) Required Probability \(=P\) (Getting Four Heads) \(+P\) (Getting 5 Heads) \(+P\) (Getting 6 Heads) \(=\frac{\frac{6 !}{4 ! 2 !}}{64}+\frac{\frac{6 !}{5 ! 1 !}}{64}+\frac{\frac{6 !}{6 !}}{64}=\frac{15}{64}+\frac{6}{64}+\frac{1}{64}=\frac{11}{32}\)…
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