AP EAMCET · Maths · Binomial Theorem
What is the remainder of \(2 x^3-5 x^2+7\) when divided with \((x-2)\) ?
- A -3
- B -2
- C 3
- D 2
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
Using remainder theorem, remainder is \(P(x=2)\). So, remainder is, \(\begin{aligned} P(x=2) & =2 \times 2^3-5 \times 2^2+7 \\ & =16-20+7 \\ & =3 \end{aligned}\)
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